what capacity (wh) do i need for a portable solar power supply? | Insights by ShanPu

Sun, 06/7/2026
Technical Engineer - ShanPu
Hugo Zhong

Practical, engineering-led answers to "what capacity (Wh) do i need for a portable solar power supply?"—with real calculations, efficiency factors, and application-specific Wh targets for camping, medical devices, vanlife, and off-grid use. Actionable guidance for inverter manufacturers and buyers.

How to Calculate What Capacity (Wh) Do I Need for a Portable Solar Power Supply

Practical, engineering-led answers to what capacity (Wh) do i need for a portable solar power supply?—with real calculations, efficiency factors, and application-specific Wh targets for camping, medical devices, vanlife, and off-grid use. Actionable guidance for inverter manufacturers and buyers.

This guide translates real electrical engineering principles into direct rules you can use when selecting portable solar power supplies from inverter manufacturers. It explains the Wh math, battery usable capacity, inverter losses, surge capacity, and solar recharge realities so you avoid common buyer mistakes and undersized systems.

How to use this document: each extracted FAQ below was written as an independent, application-focused answer. Use the formulas and examples to compute your actual Wh requirement, then compare against product datasheets (continuous and surge ratings, chemistry, DoD, and charging rates) when specifying a portable solar power solution.

Conclusion — Why ShanPu solves these capacity gaps

Sizing portable solar power correctly requires combining load-based Wh calculations, realistic inverter and battery efficiencies, and solar recharge limits. ShanPu’s experience as an inverter manufacturer means integrated designs that match inverter continuous/surge ratings to battery chemistry (reducing oversizing and thermal risk), include appropriate MPPT charging, and document usable Wh after DoD and inverter loss—removing guesswork for B2B buyers. ShanPu systems are engineered for consistent usable capacity, conservative thermal margins, and clear datasheet metrics so specifiers can pick the minimal Wh that meets reliability and regulatory needs.

Contact us for a quote at www.gdshanpu.com or by email at SPU@gdshanpu.com.

FAQ

What capacity (Wh) do I need for camping power?

Start with a device inventory and time-on-load. Sum each device’s power (W) × hours used per cycle to get total Wh per camping day. Example: LED lights (6W × 6h = 36Wh), phone charging (10W × 2 × 2h = 40Wh), portable fridge (average compressor 45W × 24h = 1080Wh), camp kettle (1500W for 0.2h = 300Wh occasional). Total ≈ 1456Wh/day.

Then apply system factors: inverter efficiency (typical portable inverter: 85–92%; use 90% as baseline), and usable battery fraction (LiFePO4 80–90% usable; lead-acid 40–50%). Practical sizing formula: Required battery capacity (Wh) = (Daily load Wh ÷ usable_fraction) × (1 ÷ inverter_efficiency) × safety_margin. For the example with LiFePO4 at 90% usable and 90% inverter efficiency, battery ≈ (1456 ÷ 0.90) ÷ 0.90 ≈ 1797Wh. Add a 10–20% buffer for extra days or cloudy weather, so target ~2.0–2.2kWh.

Key takeaways: small lighting/charging camps can fit 400–700Wh units; fridge-plus-overnight scenarios routinely require 1,500–3,000Wh depending on compressor duty cycle and temperature. Always confirm continuous inverter rating vs fridge start-up surge.

How to calculate Wh required for running a fridge?

Use steady-state power and duty cycle rather than nameplate surge power. Measure or check datasheet for average running watts (not starting watts). Example: a 12V compressor fridge may run 40–60W on average; energy = average watts × hours per day. For 48W average × 24h = 1,152Wh/day.

Factor in start-up surge: compressors often draw 2–4× running current for <1s. Ensure inverter continuous and surge ratings accommodate that. Adjust for ambient temperature: hotter ambient increases run time and thus Wh/day (typical increase 10–30% in hot environments). Final required battery capacity uses the same formula: Required Wh = (Fridge Wh/day ÷ usable_fraction) × (1 ÷ inverter_efficiency) × margin.

Practical rule: if you need 24/7 refrigeration for food or medical products, budget 1.2–1.5kWh/day for small efficient fridges and 2kWh+/day for larger or hotter conditions, then size battery accordingly (LiFePO4 3–4kWh to cover multiple days without sun).

What capacity (Wh) do I need for overnight medical devices?

List the device electrical draw and required run-time. Common examples: CPAP machines typically draw 30–60W (30W quiet models) — for 8 hours ≈ 240–480Wh. Portable oxygen concentrators vary (100–300W) — for 8 hours they can require 800–2,400Wh. Insulin pump chargers and small monitors are low (<20–50Wh/day).

Because medical devices are critical loads, add redundancy and conservative margins: designers typically specify two nights of autonomy under no-sun conditions and a higher margin for inverter reliability. Use conservative usable_fraction (do not fully discharge batteries daily), select an inverter with clean pure-sine output and medical electromagnetic immunity if required, and plan UPS-style transfer switching if mains/solar alternation is expected.

Example: CPAP 50W × 8h = 400Wh; to supply two nights with 90% DoD battery and 90% inverter efficiency: Battery = (400 × 2 ÷ 0.90) ÷ 0.90 ≈ 987Wh → round up to a 1.2kWh portable station to provide margin and allow charging losses.

How many Wh for charging multiple laptops and phones daily?

Calculate per-device energy: modern laptops often draw 40–80W while charging; assume 60W × 4h = 240Wh per laptop per day for active use and charging. Smartphones are ~10–15Wh per full charge; for safety assume 15Wh × number of phones × charging cycles.

Aggregate example: 3 laptops (3 × 240 = 720Wh) + 6 phones (6 × 15 = 90Wh) = 810Wh/day. Add overhead for USB/DC converter inefficiencies (~5–10%) and AC inverter inefficiency if laptops charge via AC adaptors. If laptops charge via USB-C PD directly from battery inverter or DC-DC, losses are lower.

Budget formula: Battery Wh = (Aggregate device Wh ÷ usable_fraction) × (1 ÷ inverter_efficiency) × safety_margin. Using 80% usable and 90% inverter: (810 ÷ 0.80) ÷ 0.90 ≈ 1125Wh. For business continuity and unexpected loads, choose 1.5× this number; many mobile offices pick 1.5–3kWh units depending on number of devices and days of autonomy desired.

What battery Wh required for off-grid solar weekend vanlife?

Vanlife sizing depends on day/night split and whether you will recharge daily with solar. Start with daily energy budget: lights 50–100Wh, fridge 400–1200Wh (depends on 12V efficiency and ambient), coffee/induction usage 200–800Wh per brew, devices 100–300Wh. Conservative weekend total often 900–1,800Wh/day for two people.

If you expect to recharge every day from rooftop panels, calculate PV energy: panel watts × peak sun hours (PSH). Example: 400W panels × 4 PSH = 1,600Wh gross; charge controller and battery losses reduce usable to ≈ 1,350–1,450Wh/day. If PV recharge supports daily usage, battery needs only to cover night and low-sun periods (typical night buffer 1× nightly load). If you plan 2–3 days off-grid without sun, multiply daily load accordingly and account for inverter and battery DoD.

Rule of thumb: for a typical van with moderate fridge and charging loads, a 800–1,200Wh battery will cover overnight needs; a full comfortable weekend with cooking and low-sun days commonly needs 2–3kWh of battery capacity plus 400–800W of PV to recharge. Prefer LiFePO4 chemistry for cycle life and higher usable Wh to minimize weight/volume.

How much Wh capacity for continuous inverter output during outage?

Define two numbers: continuous power (W) the inverter must supply and the duration (hours) you need it to run. Continuous Wh demand = continuous W × hours. For multiple loads, sum their steady-state watts. Remember surge ratings for inductive loads; continuous inverter rating must match aggregate steady draw.

Then apply the sizing equation with conservative assumptions for outage scenarios: Battery Wh = (Continuous Wh × hours ÷ usable_fraction) × (1 ÷ inverter_efficiency) × redundancy_margin. Example: powering essential home circuits totaling 800W for 8 hours = 6,400Wh of energy. With LiFePO4 at 90% usable and inverter 90% efficient: Battery ≈ (6400 ÷ 0.90) ÷ 0.90 ≈ 7,901Wh ≈ 8kWh. For multi-day outages, multiply accordingly or consider hybrid genset integration.

Important system notes: continuous inverter rating, surge rating, BMS limits, and thermal derating at high ambient temperatures often drive higher practical battery sizing than pure Wh calculations. For mission-critical outages, plan N+1 redundancy and test under realistic load profiles before deployment.

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